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4.9x^2-19.4x-74.1=0
a = 4.9; b = -19.4; c = -74.1;
Δ = b2-4ac
Δ = -19.42-4·4.9·(-74.1)
Δ = 1828.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19.4)-\sqrt{1828.72}}{2*4.9}=\frac{19.4-\sqrt{1828.72}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19.4)+\sqrt{1828.72}}{2*4.9}=\frac{19.4+\sqrt{1828.72}}{9.8} $
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